5^2x+3=7^x-1

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Solution for 5^2x+3=7^x-1 equation: 



5^2x+3=7^x-1

We move all terms to the left:

5^2x+3-(7^x-1)=0

We get rid of parentheses

5^2x-7^x+1+3=0

We add all the numbers together, and all the variables

5^2x-7^x+4=0

We move all terms containing x to the left, all other terms to the right

5^2x-7^x=-4

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